\( \frac{1}{36} \)
Since each die has 6 sides, the total number of possible outcomes when rolling both dice together is 6 x 6 = 36.
Only one of these outcomes results in rolling a 3 on both dice (3 and 3), so the probability of rolling 3 and 3 is 1 out of 36, which is \( \frac{1}{36} \).
If you have two 6-sided dice, each with the numbers 1-6 on a side, what is the theoretical probability of rolling 3 and 3 when both die are rolled together?
\( \frac{1}{6} \)
\( \frac{1}{36} \)
\( \frac{1}{12} \)
\( \frac{1}{3} \)
1 answer