The diagram below shows two resistors connected in series to a 28-volt battery. If the voltage drop across the 15-ohm resistor is 21 volts, what would be the resistance of the second resistor in the circuit?
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1 point
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3.0 ohms
4.0 ohms
5 ohms
6 ohms
3 answers
5 ohms
are you sure
Yes, I am sure. Given that the voltage drop across the 15-ohm resistor is 21 volts and the total voltage supply is 28 volts, the voltage drop across the second resistor can be calculated as follows:
Total voltage - Voltage drop across first resistor = Voltage drop across second resistor
28 V - 21 V = 7 V
The resistance of the second resistor can be calculated using Ohm's Law:
Resistance = Voltage / Current
Given that the voltage drop across the second resistor is 7 V, we need to determine the current flowing through the circuit. Since the resistors are connected in series, the current flowing through both resistors is the same.
Using Ohm's Law:
V = I * R
21 V = I * 15 Ω
I = 21 V / 15 Ω = 1.4 A
Now that we know the current, we can calculate the resistance of the second resistor:
Resistance = Voltage / Current
Resistance = 7 V / 1.4 A = 5 Ω
Therefore, the resistance of the second resistor in the circuit is 5 ohms.
Total voltage - Voltage drop across first resistor = Voltage drop across second resistor
28 V - 21 V = 7 V
The resistance of the second resistor can be calculated using Ohm's Law:
Resistance = Voltage / Current
Given that the voltage drop across the second resistor is 7 V, we need to determine the current flowing through the circuit. Since the resistors are connected in series, the current flowing through both resistors is the same.
Using Ohm's Law:
V = I * R
21 V = I * 15 Ω
I = 21 V / 15 Ω = 1.4 A
Now that we know the current, we can calculate the resistance of the second resistor:
Resistance = Voltage / Current
Resistance = 7 V / 1.4 A = 5 Ω
Therefore, the resistance of the second resistor in the circuit is 5 ohms.