Question

(?)(6y^7−8y)=−30y^13+40y^7

Answer 1

(?)(6y^7−8y)=−30y^13+40y^7

whats the missing value (?)

Answer 2

To verify the given equation, we need to simplify both sides and check if they are equal.

Given equation: (6y^7 - 8y) = -30y^13 + 40y^7

Simplify the left side:
6y^7 - 8y = 2y(3y^6 - 4)

Simplify the right side:
-30y^13 + 40y^7 = 10y^7(-3y^6 + 4)

Now compare both sides:
2y(3y^6 - 4) = 10y^7(-3y^6 + 4)

Distribute:
6y^7 - 8y = -30y^7 + 40y^7

Combine like terms:
6y^7 - 8y = 10y^7

Therefore, the given equation is verified and correct.

Answer 3

To find the missing value represented by (?), we can equate the coefficients of y on both sides of the equation.

Given equation: (?)(6y^7 - 8y) = -30y^13 + 40y^7

Let's simplify the left side first:
(?)(6y^7 - 8y) = ? * (6y^7) - ? * (8y)
(?)(6y^7 - 8y) = 6?(y^7) - 8?(y)
(?)(6y^7 - 8y) = 6?(y^7 - 8y)

Now, we equate the coefficients of y on both sides:
6? = -30 (coefficient of y^13 on the right side)
-8? = 40 (coefficient of y^7 on the right side)

To solve for ?, divide both sides of the first equation by 6:
? = -30 / 6
? = -5

Therefore, the missing value represented by (?) in the equation is -5.