Which of the following is the point on a graph is described by the function y=(2x+1)to the 2nd power -4

Answer 1

The point on the graph described by the function y = (2x + 1)^2 - 4 is the vertex of the parabola formed by the function.

To find the vertex, we need to set the derivative of the function equal to 0 and solve for x.

dy/dx = 0
4(2x + 1) = 0
8x + 4 = 0
8x = -4
x = -1/2

Now, we need to plug in x = -1/2 back into the original function to find the y-coordinate of the vertex.

y = (2(-1/2) + 1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3

Therefore, the vertex of the parabola described by the function y = (2x + 1)^2 - 4 is the point (-1/2, -3).