Question

If the surface area of the net diagram of the right circular cylinder is 395.64 feet2, find the height of the net diagram. Use 3.14 for π.

a illustration shows 2 circular cylinders that each have 3 feet with a square in-between them with an unknown height

Answer 1

wrong

Answer 2

correct the answer is 18.

Answer 3

To find the height of the net diagram, we first need to find the total surface area of the right circular cylinder.

The surface area of a right circular cylinder can be calculated using the formula:

Surface Area = 2πr^2 + 2πrh

Where:
r = radius of the base of the cylinder
h = height of the cylinder

In this case, we are given that the surface area of the net diagram is 395.64 ft^2. Since there are two cylinders, we can find the surface area of one cylinder by dividing the total surface area by 2:

395.64 ft^2 / 2 = 197.82 ft^2

Now, we can plug in the values into the formula and solve for the height:

197.82 = 2(3.14)(3)^2 + 2(3.14)(3)h
197.82 = 56.52 + 18.84h
18.84h = 141.30
h = 7.5 feet

Therefore, the height of the net diagram is 7.5 feet.

Answer 4

I apologize for the error in my previous calculation.

Let's correct it:

Given:
Total surface area of the net diagram = 395.64 ft^2

The surface area of a right circular cylinder can be calculated using the formula:

Surface Area = 2πr^2 + 2πrh

We are given that the radius of the circular cylinder is 3 feet.

Let the height of the cylinder be represented by 'h'.

Given:
r = 3 feet

Using the formula for surface area:

395.64 = 2*(3.14)*(3)^2 + 2*(3.14)*(3)*h
395.64 = 56.52 + 18.84h
339.12 = 18.84h
h = 18 feet

Therefore, the correct height of the net diagram is 18 feet.

Answer 5

Thank you for confirming. I'm glad that the correct answer aligns with the calculation. The height of the net diagram is indeed 18 feet. If you have any more questions or need further clarification, feel free to ask.