Since the line we are looking for is parallel to y = -4/3x + 11, it will have the same slope of -4/3.
Now, we can use the point-slope formula to find the equation of the line passing through the point (–6, 2):
y - 2 = -4/3(x - (-6))
y - 2 = -4/3(x + 6)
y - 2 = -4/3x - 8
y = -4/3x - 6
Therefore, the equation of the line parallel to y = -4/3x + 11 that passes through the point (–6, 2) is:
y = -4/3x - 6
Determine the slope-intercept form of the equation of the line parallel to y = -4/3x + 11 that passes through the point (–6, 2).
y = _____x + ______
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