To determine how many moles of nitrogen are needed to react with 27.6 moles of hydrogen, we first need to use the balanced equation to set up a mole to mole ratio.
From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2.
So, we can set up the following proportion:
1 mole N2 / 3 moles H2 = x moles N2 / 27.6 moles H2
Cross multiplying, we get:
3 moles H2 * x moles N2 = 1 mole N2 * 27.6 moles H2
3x = 27.6
x = 27.6 / 3
x = 9.2
Therefore, 9.2 moles of nitrogen (N2) are needed to react with 27.6 moles of hydrogen (H2).
The correct answer is:
c) 9.2 mol of Nitrogen
The following balanced equation shows the formation of ammonia. N2 + 3H2 2NH3 How many moles of nitrogen (N2) are needed to react with 27.6 moles of hydrogen (H2)? If you are unsure how to do a mole to mole conversion, please see the example problem linked HERE. a 82.8 mol of Nitrogen b 6.1 mol of Nitrogen c 9.2 mol of Nitrogen d 24.6 mol of Nitrogen
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