Question

The following balanced equation shows the formation of ammonia. N2 + 3H2 2NH3 How many moles of nitrogen (N2) are needed to react with 27.6 moles of hydrogen (H2)? If you are unsure how to do a mole to mole conversion, please see the example problem linked HERE. a 82.8 mol of Nitrogen b 6.1 mol of Nitrogen c 9.2 mol of Nitrogen d 24.6 mol of Nitrogen

Answer 1

To determine how many moles of nitrogen are needed to react with 27.6 moles of hydrogen, we first need to use the balanced equation to set up a mole to mole ratio.

From the balanced equation, we can see that 1 mole of N2 reacts with 3 moles of H2.

So, we can set up the following proportion:

1 mole N2 / 3 moles H2 = x moles N2 / 27.6 moles H2

Cross multiplying, we get:

3 moles H2 * x moles N2 = 1 mole N2 * 27.6 moles H2
3x = 27.6
x = 27.6 / 3
x = 9.2

Therefore, 9.2 moles of nitrogen (N2) are needed to react with 27.6 moles of hydrogen (H2).

The correct answer is:
c) 9.2 mol of Nitrogen