If the diameter of a small red beach ball is 8 inches, then the cone with the same radius and a height of 8 inches would fit into the beach ball blank times and the volume of the cone would be about . blank in^3.
fill in the blanks
3 answers
The cone would fit into the beach ball approximately 6 times, and the volume of the cone would be about 134.04 in^3.
just asking could u work this out so i could see how
Sure! Let's calculate the volume of the cone first.
The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius and h is the height.
Given that the radius of the cone is the same as the diameter of the beach ball, the radius of the cone is 4 inches (half of 8 inches).
So, plugging in the values we have:
V = (1/3)π(4)^2(8)
V = (1/3)π(16)(8)
V = (1/3)π(128)
V ≈ 134.04 in^3
The volume of the cone would be approximately 134.04 in^3.
Next, let's calculate how many times this cone can fit into the beach ball.
The volume of the beach ball can be calculated using the formula for the volume of a sphere, V = (4/3)πr^3, where r is the radius.
Given that the diameter of the beach ball is 8 inches, the radius of the beach ball is 4 inches.
So, plugging in the values we have:
V = (4/3)π(4)^3
V = (4/3)π(64)
V ≈ 268.08 in^3
Now, to find out how many times the cone can fit into the beach ball, we divide the volume of the beach ball by the volume of the cone:
Approximately 268.08 in^3 / 134.04 in^3 = 2
Therefore, the cone would fit into the beach ball about 2 times.
The formula for the volume of a cone is V = (1/3)πr^2h, where r is the radius and h is the height.
Given that the radius of the cone is the same as the diameter of the beach ball, the radius of the cone is 4 inches (half of 8 inches).
So, plugging in the values we have:
V = (1/3)π(4)^2(8)
V = (1/3)π(16)(8)
V = (1/3)π(128)
V ≈ 134.04 in^3
The volume of the cone would be approximately 134.04 in^3.
Next, let's calculate how many times this cone can fit into the beach ball.
The volume of the beach ball can be calculated using the formula for the volume of a sphere, V = (4/3)πr^3, where r is the radius.
Given that the diameter of the beach ball is 8 inches, the radius of the beach ball is 4 inches.
So, plugging in the values we have:
V = (4/3)π(4)^3
V = (4/3)π(64)
V ≈ 268.08 in^3
Now, to find out how many times the cone can fit into the beach ball, we divide the volume of the beach ball by the volume of the cone:
Approximately 268.08 in^3 / 134.04 in^3 = 2
Therefore, the cone would fit into the beach ball about 2 times.