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A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical car at rest. If the cars lock together as a resu...Asked by Jeremy
A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical car at rest. If the cars lock together as a result of the collision, what is their common speed afterward?
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Answered by
drwls
Apply the law of conservation of momentum to this problem
10,000 * 24.0 = V' * 20,000
V' is the final velocity after collision. Solve for it.
10,000 * 24.0 = V' * 20,000
V' is the final velocity after collision. Solve for it.
Answered by
omer
A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical car at rest. If the cars lock together as a result of the collision, what is their common speed afterward?
Answered by
habimana
A 10,000 kg railroad car traveling at a speed of 24.0 m/s strikes an identical car at rest. If the cars lock together as a result of the collision, what is their common speed afterward?
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