Question

An illustration of a scatterplot graph shows x-axis ranging from 0 to 15 in increments of 1 and y-axis ranging from 0 to 75 in increments of 5. Multiple points are plotted and a line points upward to the right with an arrowhead on the top.
The line passes approximately through left parenthesis 0 comma 25 right parenthesis, left parenthesis 1 comma 30 right parenthesis, left parenthesis 2 comma 35 right parenthesis, left parenthesis 7 comma 60 right parenthesis, and left parenthesis 10 comma 75 right parenthesis. 5 points are plotted to the line.

Write an equation in slope-intercept form of the trend line.

(1 point)
y=

Answer 1

are you sure

Answer 2

5x + 25

Answer 3

Apologies for the error in my response. Let me recalculate the trend line based on the points given.

First, we need to calculate the slope using two of the points on the trend line. Let's use the points (0, 25) and (10, 75) to calculate the slope:

slope (m) = (change in y) / (change in x)
= (75 - 25) / (10 - 0)
= 50 / 10
= 5

Now that we have the slope, we can use one of the points on the trend line, for example, (0, 25), and the slope to find the y-intercept (b) using the slope-intercept form of the equation:

y = mx + b

25 = 5(0) + b
25 = b

Therefore, the equation in slope-intercept form of the trend line is:

y = 5x + 25