Asked by Christy
I have been able to figure out everything on my assignment but this one. Can anyone help?
Five numbers are to be picked, without repetition from 44 numbers to determine the winner of the Fortune Five game in the state lottery. If the order of the numbers is insignificant, how many different ways can a winning quintuple be selected? What is the probability of winning?
Five numbers are to be picked, without repetition from 44 numbers to determine the winner of the Fortune Five game in the state lottery. If the order of the numbers is insignificant, how many different ways can a winning quintuple be selected? What is the probability of winning?
Answers
Answered by
Reiny
The number of ways to choose 5 out of 44 numbers is
C(44,5) = 44!/(5!39!) = 1086008
So the prob of winning is 1/1086008
C(44,5) = 44!/(5!39!) = 1086008
So the prob of winning is 1/1086008
Answered by
Christy
Thank you, now I feel really dumb. Ive been pondering this question for an hour or two.
Answered by
Anonymous
A blueprint for a museum uses a scale of a 1/4 in:1ft. One of the rooms on the blueprint is 3 3/4 in. long. How long is the actual room?
Answered by
Abel R.
3 3/4in -> 15/4 -> 3.75
0.25 in. 3.75
-------- = ------- Now cross multiply
1ft. X
X= 15ft
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