To find the height of the ball at t = 3 seconds, we plug t = 3 into the equation for h:
h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 180 + 6
h = 42
Therefore, the height of the ball at t = 3 seconds will be 42 feet.
a ball is thrown into the air with initial velocity of 60 ft/s. its height (h) in feet after t seconds is given by the function h =-16t^2 + 60t + 6. What will the height be at t = 3 seconds
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