Question
Calculate The number of aluminium ions in 0.056g of aluminium oxide?
Answers
GPT 3.5
To calculate the number of aluminum ions in 0.056g of aluminum oxide, we first need to determine the molar mass of aluminum oxide.
The molar mass of aluminum oxide (Al2O3) is:
Aluminum (Al) = 26.98 g/mol
Oxygen (O) = 16.00 g/mol
Molar mass of Al2O3 = 2(Al) + 3(O) = 2(26.98) + 3(16.00) = 54.06 + 48.00 = 102.06 g/mol
Now, we can calculate the number of moles of aluminum oxide present in 0.056g:
Number of moles = Mass / Molar mass
Number of moles = 0.056g / 102.06 g/mol ≈ 0.000548 moles
Since there are 2 aluminum ions in one molecule of aluminum oxide, the number of aluminum ions present in 0.056g of aluminum oxide is:
Number of aluminum ions = 2 * 0.000548 ≈ 0.0011 moles
Therefore, there are approximately 0.0011 moles of aluminum ions in 0.056g of aluminum oxide.
The molar mass of aluminum oxide (Al2O3) is:
Aluminum (Al) = 26.98 g/mol
Oxygen (O) = 16.00 g/mol
Molar mass of Al2O3 = 2(Al) + 3(O) = 2(26.98) + 3(16.00) = 54.06 + 48.00 = 102.06 g/mol
Now, we can calculate the number of moles of aluminum oxide present in 0.056g:
Number of moles = Mass / Molar mass
Number of moles = 0.056g / 102.06 g/mol ≈ 0.000548 moles
Since there are 2 aluminum ions in one molecule of aluminum oxide, the number of aluminum ions present in 0.056g of aluminum oxide is:
Number of aluminum ions = 2 * 0.000548 ≈ 0.0011 moles
Therefore, there are approximately 0.0011 moles of aluminum ions in 0.056g of aluminum oxide.