The correct answer is 38 ft.2 or 38 square feet.
To find the area of the spaceship, we first need to calculate the area of the rectangle:
Area = length x width = 8 ft x 4 ft = 32 square feet
Then, we need to calculate the area of the two right triangles:
Area of one triangle = 0.5 x base x height = 0.5 x 2 ft x 3 ft = 3 square feet
Area of two triangles = 2 x 3 square feet = 6 square feet
Total area of the spaceship = area of rectangle + area of triangles
Total area = 32 ft2 + 6 ft2 = 38 ft2
Use the image to answer the question.
A horizontal rectangle is shown with two small right triangles extending above and below on the left side of the rectangle. The overall length of the horizontal rectangle is 8 feet, and the width is 4 feet. The two right triangles extend outward top and bottom from the left width side of the rectangle by 2 feet each. The sides of the triangles that are common to the length of the rectangle are labeled as 3 feet.
Mr. Ming’s second grade class is making a mural to celebrate the completion of their unit on astronomy. The image of the spaceship will be central to the mural. What is the area of the spaceship?
(1 point)
Responses
32 ft.2
32 ft. squared
38 ft.2
38 ft. squared
35 ft.2
pick the right answer
1 answer