Asked by Tammy
A car with good tires on a dry road can decelerate at about 5 m/s^2 when breaking. Suppose a car is initially traveling at 65 mph. What is the stopping distance?(give answer in meters and in feet)
I changed 65mph into 29.05m/s. so I would use d-d_0 = (v^2 -v_0^2)/2a
and when I did this I got 84.39m and when this is converted into ft I got 276.87 ft. Is this correct? Thanks in advance for your help.
I changed 65mph into 29.05m/s. so I would use d-d_0 = (v^2 -v_0^2)/2a
and when I did this I got 84.39m and when this is converted into ft I got 276.87 ft. Is this correct? Thanks in advance for your help.
Answers
Answered by
bobpursley
Yes, do that formula. Your answers are correct.
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