A poll is conducted to determine who is most likely to win the election for town mayor two random samples of 500 residents each are polled. The data is as follows sample one for candidate. A 346 candidate is 154 for a total of 500 sample two for candidate a 248 candidate is 252 total 500 which percentage of the total poll residence would vote for candidate as the town mayor.

1 answer

For sample one, candidate A received 346 votes out of 500, which is 346/500 = 0.692 or 69.2%.

For sample two, candidate A received 248 votes out of 500, which is 248/500 = 0.496 or 49.6%.

To calculate the percentage of the total poll residence that would vote for candidate A, we need to combine the votes from both samples.

Total votes for candidate A = 346 + 248 = 594

Total votes in the poll = 500 + 500 = 1000

Percentage of total poll residence that would vote for candidate A = 594/1000 = 0.594 or 59.4%

Therefore, 59.4% of the total poll residence would vote for candidate A as the town mayor.