2 IDENTICAL CUPS AND 3 IDENTICAL PLATES COST DOLLER 14.3SUCH CUPS AND 2 PLATES COST DOLLER13.WHAT IS THE TOTAL COST OF 1 SUCH CUP AND 1 SUCH PLA?

Let's represent the cost of 1 cup as C and the cost of 1 plate as P.

According to the given information, we have the following two equations:

2C + 3P = 14 (Equation 1)
2C + 2P = 13 (Equation 2)

Subtracting Equation 2 from Equation 1, we get:
P = 1

Now, substitute the value of P in Equation 2:

2C + 2(1) = 13
2C + 2 = 13
2C = 11
C = 5.5

Therefore, the total cost of 1 cup and 1 plate is:
5.5 + 1 = $6.5.