Use the image to answer the question.

The net appears as three horizontal rectangles joined one on top of the other. The top, left, and bottom sides of the middle rectangle are drawn with dashed lines. The height of the middle rectangle is 40 millimeters. The width of the middle rectangle is 10 millimeters. The middle rectangle has a right triangle adjoining its left side. The top horizontal side of the triangle is 9 millimeters. The right side of the bottom rectangle is dashed and is 41 millimeters. An unmarked triangle the same size and shape as the other triangle adjoins the right side of the bottom rectangle. Its hypotenuse shares a side with the right side of the bottom rectangle.

The net of a triangular prism is shown. What is the surface area of the triangular prism?

(1 point)
Responses

1,080 mm.2
1,080 mm.2

1,220 mm.2
1,220 mm.2

1,260 mm.2
1,260 mm.2

1,620 mm.2
1,620 mm.2
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1 answer

To find the surface area of the triangular prism, you need to find the area of all the faces and then add them up.

1. The top and bottom faces are both triangles with base 10 mm and height 9 mm, so their area is (1/2)*10*9 = 45 mm^2 each.

2. The two side faces are rectangles, one with dimensions 40 mm by 9 mm, and the other with dimensions 40 mm by 41 mm. Their areas are 40*9 = 360 mm^2 and 40*41 = 1640 mm^2.

Adding up all the areas: 45 (top) + 45 (bottom) + 360 (side) + 1640 (side) = 2090 mm^2.

Therefore, the surface area of the triangular prism is 2090 mm^2.