The surface area of the triangular prism can be calculated by finding the area of each individual rectangle and triangle and then adding them up.
The net consists of two rectangles with dimensions 2.5 cm by 1 cm, which gives an area of 2.5 cm x 1 cm = 2.5 cm^2 each. The total area of the two outer rectangles is therefore 2 x 2.5 cm^2 = 5 cm^2.
The middle rectangle has dimensions 3 cm by 1 cm, giving an area of 3 cm x 1 cm = 3 cm^2.
The two triangles have a base of 1 cm and a height of 2 cm, so the area of each triangle is 0.5 x 1 cm x 2 cm = 1 cm^2. Since there are 2 triangles, the total area is 2 x 1 cm^2 = 2 cm^2.
Adding up the areas of all the shapes, we get:
5 cm^2 (outer rectangles) + 3 cm^2 (middle rectangle) + 2 cm^2 (triangles) = 10 cm^2.
Therefore, the surface area of the triangular prism is 10 cm^2.
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three horizontal rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the 3 rectangles is 1 centimeter. The length of the outer rectangles is 2.5 centimeters. The length of the middle rectangle is 3 centimeters. Two right triangles adjoin the middle rectangle on the top and bottom along the 3 centimeter side, with their perpendicular height measuring 2 centimeters. A right angle is shown where the perpendicular height intersects with the triangle base.
What is the surface area of the triangular prism whose net is shown?
(1 point)
Responses
8 cm2
8 cm squared
14 cm2
14 cm squared
2.48 cm2
2.48 cm squared
6 cm2
6 cm squared
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1 answer