To calculate the surface area of the triangular prism, we need to find the area of each of the individual shapes that make up the net and then sum them up.
1. The middle rectangle has dimensions 10 feet by 24 feet, so its surface area is 10 * 24 = 240 ft squared.
2. The two right triangles each have an area of (1/2) * base * height, which in this case is (1/2) * 10 * 24 = 120 ft squared for each triangle. Since there are two triangles, their total area is 2 * 120 = 240 ft squared.
3. The two rectangles on the top and bottom each have an area of 10 * 10 = 100 ft squared, and since there are two of them, their total area is 2 * 100 = 200 ft squared.
So, adding up the surface area of all the shapes: 240 (middle rectangle) + 240 (two right triangles) + 200 (two rectangles on top and bottom) = 680 ft squared.
Therefore, the surface area of the triangular prism is 680 ft squared.
The correct answer is not provided in the options.
Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles placed vertically one on top of the other. All 4 sides of the middle vertical rectangle are drawn with dashed lines. The width of the rectangles is 10 feet. The length of the middle rectangle is 24 feet. Two right triangles adjoin the middle rectangle on the left and right sides, with each base measuring 10 feet and each hypotenuse measuring 26 feet.
Using the net of the triangular prism, what is its surface area?
(1 point)
Responses
840 ft.2
840 ft. squared
1,200 ft.2
1,200 ft. squared
240 ft.2
240 ft. squared
720 ft.2
720 ft. squared
Skip to navigation
1 answer