Question
Which set of events is dependent?(1 point)
the event of getting two heads when flipping two fair coins
choosing a marble from a box, replacing it, then choosing another marble
rolling a number cube and flipping a coin
choosing a ball from a bag and then choosing another ball without replacing the first
the event of getting two heads when flipping two fair coins
choosing a marble from a box, replacing it, then choosing another marble
rolling a number cube and flipping a coin
choosing a ball from a bag and then choosing another ball without replacing the first
Answers
Answer
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected
without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
without replacement. Calculate the probability of selecting an apple and a banana.(1 point)
Answer
whats that fractioned?
Answered by
GPT 3.5
the event of getting two heads when flipping two fair coins
Answered by
GPT 3.5
First, calculate the total number of ways to select 2 fruits from the basket:
Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Number of ways to select 2 fruits from 20 = 20C2 = (20!)/(2!(20-2)!) = 190
Next, calculate the number of ways to select 1 apple and 1 banana:
Number of ways to select 1 apple = 7C1 = 7
Number of ways to select 1 banana = 5C1 = 5
Total number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Calculate the probability of selecting an apple and a banana:
Probability = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits
Probability = 35 / 190
Probability ≈ 0.1842
Therefore, the probability of selecting an apple and a banana is approximately 0.1842.
Total number of fruits = 5 (bananas) + 8 (mangoes) + 7 (apples) = 20 fruits
Number of ways to select 2 fruits from 20 = 20C2 = (20!)/(2!(20-2)!) = 190
Next, calculate the number of ways to select 1 apple and 1 banana:
Number of ways to select 1 apple = 7C1 = 7
Number of ways to select 1 banana = 5C1 = 5
Total number of ways to select 1 apple and 1 banana = 7 * 5 = 35
Calculate the probability of selecting an apple and a banana:
Probability = Number of ways to select an apple and a banana / Total number of ways to select 2 fruits
Probability = 35 / 190
Probability ≈ 0.1842
Therefore, the probability of selecting an apple and a banana is approximately 0.1842.
Answered by
GPT 3.5
To express the probability as a fraction, you can simplify it by dividing the numerator and denominator by their greatest common divisor, which is 5 in this case.
35/190 = (35 ÷ 5) / (190 ÷ 5) = 7/38
So, the probability of selecting an apple and a banana is 7/38.
35/190 = (35 ÷ 5) / (190 ÷ 5) = 7/38
So, the probability of selecting an apple and a banana is 7/38.