To determine the greatest efficiency, we need to calculate the fuel consumption for each situation in liters per kilometer.
A. 5.0 liters / 70 km = 0.071 liters/km
B. 4.0 liters / 50 km = 0.08 liters/km
C. 5.0 liters / 80 km = 0.0625 liters/km
D. 6.0 liters / 90 km = 0.0667 liters/km
Therefore, the car that achieved the greatest efficiency is car C, which traveled 80 kilometers on 5.0 liters of gas, with a consumption of 0.0625 liters per kilometer.
in which situation did the car achieve the greatest efficiency (assume the cars all have the same mass)
A. a car that traveled 70 kilometers on 5.0 liters of gas
B. a car that traveled 50 kilometers on 4.0 liters of gas
C. a car that traveled 80 kilometers on 5.0 liters of gas.
D. a car that traveled 90 kilometers on 6.0 liters of gas
1 answer
1 answer