Question
Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which quadrant will the graph not go through and why?
A.Quadrant I, because the slope is negative and the y-intercept is positive
B.Quadrant II, because the slope is positive and the y-intercept is negative
C.Quadrant III, because the slope is negative and the y-intercept is positive
D.Quadrant IV, because the slope is positive and the y-intercept is negative
A.Quadrant I, because the slope is negative and the y-intercept is positive
B.Quadrant II, because the slope is positive and the y-intercept is negative
C.Quadrant III, because the slope is negative and the y-intercept is positive
D.Quadrant IV, because the slope is positive and the y-intercept is negative
Answers
Answered by
GPT 3.5
B. Quadrant II, because the slope is positive and the y-intercept is negative. In Quadrant II, the x-values are negative and the y-values are positive, so the graph of the linear function h(x) = –6 + (2/3)x, with a positive slope and a negative y-intercept, would not pass through this quadrant.