Asked by Koleta miriama vurai
A company that manufactures wines claim that red wine contains 14.1% by volume of ethanol ( density of ethanol is 0.789g/ cm³) . Calculate the following: molality of ethanol, molarity of ethanol, % by mass of ethanol, ppm and ppb by mass of ethanol.
Answers
Answered by
GPT 3.5
To calculate the molality of ethanol:
First, we need to convert the volume percent of ethanol to weight percent. Using the density of ethanol, we can convert the volume percent to weight percent:
Volume of ethanol in 100 mL of red wine = 14.1 mL
Mass of ethanol in 100 mL of red wine = 14.1 mL * 0.789 g/mL = 11.109 g
Now, we can calculate the molality of ethanol:
Mass of ethanol = 11.109 g
Molar mass of ethanol = 46.07 g/mol
Mass of solvent (water) = 100 g (since we are assuming the density of water is 1 g/mL)
Molality = (11.109 g / 46.07 g/mol) / 0.1 kg = 0.241 mol/kg
Next, to calculate the molarity of ethanol, we need to consider the volume of the entire solution (not just the ethanol) and calculate the number of moles of ethanol in that volume:
Volume of red wine = 100 mL
Molarity = (11.109 g / 46.07 g/mol) / (100 mL / 1000) L = 0.0241 mol/L
To calculate the % by mass of ethanol in red wine:
% by mass = (11.109 g / 100 g) * 100% = 11.109%
To calculate the ppm by mass of ethanol in red wine:
ppm = (11.109 g / 1000 g) * 10^6 = 11109 ppm
To calculate the ppb by mass of ethanol in red wine:
ppb = (11.109 g / 1000 g) * 10^9 = 11109000 ppb
Therefore, the molality of ethanol in the red wine is 0.241 mol/kg, the molarity is 0.0241 mol/L, the % by mass is 11.109%, the ppm is 11109 ppm, and the ppb is 11109000 ppb.
First, we need to convert the volume percent of ethanol to weight percent. Using the density of ethanol, we can convert the volume percent to weight percent:
Volume of ethanol in 100 mL of red wine = 14.1 mL
Mass of ethanol in 100 mL of red wine = 14.1 mL * 0.789 g/mL = 11.109 g
Now, we can calculate the molality of ethanol:
Mass of ethanol = 11.109 g
Molar mass of ethanol = 46.07 g/mol
Mass of solvent (water) = 100 g (since we are assuming the density of water is 1 g/mL)
Molality = (11.109 g / 46.07 g/mol) / 0.1 kg = 0.241 mol/kg
Next, to calculate the molarity of ethanol, we need to consider the volume of the entire solution (not just the ethanol) and calculate the number of moles of ethanol in that volume:
Volume of red wine = 100 mL
Molarity = (11.109 g / 46.07 g/mol) / (100 mL / 1000) L = 0.0241 mol/L
To calculate the % by mass of ethanol in red wine:
% by mass = (11.109 g / 100 g) * 100% = 11.109%
To calculate the ppm by mass of ethanol in red wine:
ppm = (11.109 g / 1000 g) * 10^6 = 11109 ppm
To calculate the ppb by mass of ethanol in red wine:
ppb = (11.109 g / 1000 g) * 10^9 = 11109000 ppb
Therefore, the molality of ethanol in the red wine is 0.241 mol/kg, the molarity is 0.0241 mol/L, the % by mass is 11.109%, the ppm is 11109 ppm, and the ppb is 11109000 ppb.