Question

The graph of a quadratic function is shown on the grid. Which function is best represented by the graph?
f(x)=-x^2+12
f(x)=-1/3x^2+12
f(x)=-x^2-x+6
f(x)=-1/3x^2-x+6

Answer 1

f(x)=-1/3x^2+12

Answer 2

Given g(x)=x^2-5x-14, which statement is true

Answer 3

The statement would depend on the choices provided. Can you provide the options?

Answer 4

The zeros are -7 and -2 because the factors are (x-7) and (x+2)
The zeros are 7 and -2 because the factors are (x-7) and (x+2)
The zeros are 2 and -7 because the factors are (x-2) and (x+7)
The zeros are 2 and 7 because the factors are (x-2) and (x-7)

Answer 5

The correct statement is: "The zeros are -7 and 2 because the factors are (x+7) and (x-2)."

Answer 6

m^2+16m=-55

Answer 7

To solve the quadratic equation m^2 + 16m = -55, we first rewrite it in standard form by moving all terms to one side to get:

m^2 + 16m + 55 = 0

Now, we have a quadratic equation of the form ax^2 + bx + c = 0, where a = 1, b = 16, and c = 55.

Next, we need to factor or use the quadratic formula to solve for m. In this case, we can see that the equation will not factor easily. Therefore, we will use the quadratic formula:

m = (-b ± √(b^2 - 4ac)) / 2a

Plugging in our values, we get:

m = (-16 ± √(16^2 - 4*1*55)) / 2*1
m = (-16 ± √(256 - 220)) / 2
m = (-16 ± √36) / 2
m = (-16 ± 6) / 2

So, the solutions are:
m = (-16 + 6) / 2 = -10 / 2 = -5
m = (-16 - 6) / 2 = -22 / 2 = -11

Therefore, the solutions to the equation m^2 + 16m = -55 are m = -5 and m = -11.