B. 1/4
There are three odd numbers (1, 3, 5) and three even numbers (2, 4, 6) on a six-sided cube. The probability of rolling an odd number on the first roll is 3/6 or 1/2. Then, the probability of rolling an even number on the second roll is 3/6 or 1/2.
Multiplying the probabilities together, we get (1/2) * (1/2) = 1/4.
What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?
A. 1/2
B. 1/4
C. 1
D. 2
3 answers
A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express the answer in the simplest form of fraction.
The total number of flowers in the vase is 5 (begonias) + 6 (carnations) + 7 (tulips) = 18 flowers.
The probability of selecting the first carnation is 6/18.
After one carnation has been selected, there are now 5 carnations left out of the remaining 17 flowers.
So, the probability of selecting the second carnation is 5/17.
Multiplying these probabilities together, we get (6/18) * (5/17) = 30/306 = 5/51.
Therefore, the probability of selecting two carnations is 5/51.
The probability of selecting the first carnation is 6/18.
After one carnation has been selected, there are now 5 carnations left out of the remaining 17 flowers.
So, the probability of selecting the second carnation is 5/17.
Multiplying these probabilities together, we get (6/18) * (5/17) = 30/306 = 5/51.
Therefore, the probability of selecting two carnations is 5/51.
1 answer