To find the value of x, we need to first understand that the sum of all probabilities in a probability model should add up to 1.
Therefore, we can calculate x by adding up the given probabilities and subtracting it from 1:
0.25 + 0.18 + 0.30 + 0.17 + x = 1
0.9 + x = 1
x = 1 - 0.9
x = 0.1
Therefore, the value of x is 0.1.
If the table below represents a probability model based on observed frequencies, What is the value of x?
Y C A R E S
P(Y) 0.25 0.18 0.30 0.17 x
5 answers
Pick an answer from this
A. 0.01
B. 0.10
C. 0.20
D. 1
A. 0.01
B. 0.10
C. 0.20
D. 1
B. 0.10
Number of white balls selected Number of red balls selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B
A. 200
B. 100
C. 300
D. 50
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B
A. 200
B. 100
C. 300
D. 50
To find the estimated difference in the expected number of white and red balls in Bowl B, we first need to find the expected number of white and red balls in Bowl B.
In Bowl B, there are 60 white balls and 40 red balls out of a total of 500 balls.
The estimated expected number of white balls in Bowl B = (60/500) * 500 = 60
The estimated expected number of red balls in Bowl B = (40/500) * 500 = 40
The estimated difference in the expected number of white and red balls in Bowl B = 60 - 40 = 20
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 20. None of the listed answer choices is 20.
Is this answer helpful or do you need further assistance?
In Bowl B, there are 60 white balls and 40 red balls out of a total of 500 balls.
The estimated expected number of white balls in Bowl B = (60/500) * 500 = 60
The estimated expected number of red balls in Bowl B = (40/500) * 500 = 40
The estimated difference in the expected number of white and red balls in Bowl B = 60 - 40 = 20
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 20. None of the listed answer choices is 20.
Is this answer helpful or do you need further assistance?