To find the probability that the first roll was a 4 or the sum of the two rolls was 6, we need to find the total number of favorable outcomes and divide by the total number of possible outcomes.
First, let's find the favorable outcomes:
- The first roll is a 4: There are 1 favorable outcome.
- The sum of the two rolls is 6: There are 5 favorable outcomes (1+5, 2+4, 3+3, 4+2, 5+1).
Total number of favorable outcomes = 1 (First roll is 4) + 5 (Sum is 6) = 6
Next, let's find the total number of possible outcomes:
There are 6 possible outcomes for the first roll and 6 possible outcomes for the second roll, so there are 6 * 6 = 36 total possible outcomes.
Now, we can calculate the probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 6 / 36
Probability = 1 / 6
Therefore, the probability that the first roll was a 4 or the sum of the two rolls was 6 is 1/6.
Use the table to answer the question. Roll 2 Roll 1 1 2 3 4 5 6 1 2 3 4 5 6 7 2 3 4 5 6 7 8 3 4 5 6 7 8 9 4 5 6 7 8 9 10 5 6 7 8 9 10 11 6 7 8 9 10 11 12 The table illustrates the sum of two rolls of a number cube. What is the probability that the first roll was a 4 or the sum of the two rolls was 6? Leave your answer as a reduced fraction. (1 point)
3 answers
This is wrong it is not 1/6.
I apologize for the mistake. Let's correct it.
The favorable outcomes for the event "the first roll was a 4 or the sum of the two rolls was 6" are as follows:
- First roll is a 4: There is 1 favorable outcome (4, 1-6).
- Sum of the two rolls is 6: There are 5 favorable outcomes (1,5; 2,4; 3,3; 4,2; 5,1).
Total number of favorable outcomes = 1 (First roll is 4) + 5 (Sum is 6) = 6
The total number of possible outcomes is 6 (for the first roll) multiplied by 6 (for the second roll) = 36.
Now, we can calculate the probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 6 / 36
Probability = 1 / 6
Therefore, the probability that the first roll was a 4 or the sum of the two rolls was 6 is 1/6.
The favorable outcomes for the event "the first roll was a 4 or the sum of the two rolls was 6" are as follows:
- First roll is a 4: There is 1 favorable outcome (4, 1-6).
- Sum of the two rolls is 6: There are 5 favorable outcomes (1,5; 2,4; 3,3; 4,2; 5,1).
Total number of favorable outcomes = 1 (First roll is 4) + 5 (Sum is 6) = 6
The total number of possible outcomes is 6 (for the first roll) multiplied by 6 (for the second roll) = 36.
Now, we can calculate the probability:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 6 / 36
Probability = 1 / 6
Therefore, the probability that the first roll was a 4 or the sum of the two rolls was 6 is 1/6.