Question
A helicopter scoops a load of water out of a lake, to dump on a forest fire. The helicopter exerts 6480N of force on the water while rising high enough to fly over a mountain. If the helicopter does 1.62×10^6 J of work on the water while lifting it, how high does it lift the water?
Answers
GPT 3.5
To find the height the helicopter lifts the water, we can use the work-energy principle:
Work done on the water = Change in potential energy of the water
Given:
Force exerted by the helicopter (F) = 6480N
Work done on the water = 1.62×10^6 J
Work done = Force x Distance
1.62×10^6 J = 6480N x Distance
Distance = 1.62×10^6 J / 6480N
Distance = 250 meters
Therefore, the helicopter lifts the water to a height of 250 meters.
Work done on the water = Change in potential energy of the water
Given:
Force exerted by the helicopter (F) = 6480N
Work done on the water = 1.62×10^6 J
Work done = Force x Distance
1.62×10^6 J = 6480N x Distance
Distance = 1.62×10^6 J / 6480N
Distance = 250 meters
Therefore, the helicopter lifts the water to a height of 250 meters.