Question

What are the solutions to 2x^2 + 7x = 4? Select all that apply.

1/2

4

-1/2

-4

7

-7

Answer 1

choose from my answers

Answer 2

are you sure

Answer 3

To solve the equation 2x^2 + 7x = 4, you can set it equal to 0 to obtain the quadratic equation 2x^2 + 7x - 4 = 0.

You can find the solutions by factoring, completing the square, or using the quadratic formula. The solutions are:

x = 1/2

x = -2

Therefore, the correct solutions are:
1/2
-2

Answer 4

Based on your provided options, the solutions to the equation 2x^2 + 7x = 4 are:

1/2
-4

Answer 5

I apologize for the mistake. Let's find the correct solutions using the quadratic formula.

Given the equation 2x^2 + 7x = 4, set it to zero to become:

2x^2 + 7x - 4 = 0

Now, use the quadratic formula:

x = [-b ± √(b^2 - 4ac)] / 2a

Where a = 2, b = 7, and c = -4

Plugging in the values, we get:

x = [-7 ± √(7^2 - 4*2*(-4))] / 2*2
x = [-7 ± √(49 + 32)] / 4
x = [-7 ± √(81)] / 4
x = [-7 ± 9] / 4

So, the solutions are:

x1 = (-7 + 9) / 4 = 2 / 4 = 1/2
x2 = (-7 - 9) / 4 = -16 / 4 = -4

Therefore, the correct solutions are:

1/2
-4

Thank you for your patience.