First, we need to find f(x+5).
f(x+5) = (x+5)^2 + 3(x+5) - 10
f(x+5) = x^2 + 10x + 25 + 3x + 15 - 10
f(x+5) = x^2 + 13x + 30
Therefore, k = 13.
To find the smallest zero of f(x+5), we set f(x+5) = 0 and solve for x:
x^2 + 13x + 30 = 0
(x + 3)(x + 10) = 0
x = -3 or x = -10
The smallest zero of f(x+5) is x = -10.
the function f is defined by f(x) = x^2 + 3x - 10.
if f(x+5) = x^2 + kx + 30, k = _______ find the smallest zero of f(x + 5). x = ______
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