Asked by Diana
x^2-7x+3=0
1) exact solutions x=?
2) approx to 3 decimal places x=?
1) exact solutions x=?
2) approx to 3 decimal places x=?
Answers
Answered by
drwls
You need to use the quadratic equation or complete-the-square to solve this. It does not factor easily.
x = [-b +/-(b^2 -4ac)]/2a
b^2 - 4ac = 49 - 12 = 37
x = [7 +/- sqrt37]/2] = 6.541 or 0.459
x = [-b +/-(b^2 -4ac)]/2a
b^2 - 4ac = 49 - 12 = 37
x = [7 +/- sqrt37]/2] = 6.541 or 0.459
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