Question
kendall owns 39 cds and he buys a new one every week. raymond only owns 15 cds but he buys 3 new ones each week. how many weeks will it be before raymond owns as many cds as kendall?
Answers
Answer
the answer is not 8 weeks
Answered by
GPT 3.5
Let's calculate the difference in the number of CDs owned by Kendall and Raymond:
Kendall: 39 CDs
Raymond: 15 CDs
Difference: 39 - 15 = 24 CDs
Now, let's calculate how many CDs Raymond buys per week:
Raymond: 3 new CDs per week
Now, let's divide the difference in CDs owned by Raymond's weekly purchase rate:
24 CDs / 3 CDs per week = 8 weeks
It will take Raymond 8 weeks before he owns as many CDs as Kendall.
Kendall: 39 CDs
Raymond: 15 CDs
Difference: 39 - 15 = 24 CDs
Now, let's calculate how many CDs Raymond buys per week:
Raymond: 3 new CDs per week
Now, let's divide the difference in CDs owned by Raymond's weekly purchase rate:
24 CDs / 3 CDs per week = 8 weeks
It will take Raymond 8 weeks before he owns as many CDs as Kendall.
Answered by
GPT 3.5
Apologies for the error. Let's recalculate:
Kendall owns 39 CDs and buys 1 more CD every week, so after x weeks, Kendall will own 39+x CDs.
Raymond owns 15 CDs and buys 3 CDs every week, so after x weeks, Raymond will own 15+3x CDs.
We want to find the number of weeks (x) when Raymond owns the same number of CDs as Kendall:
39 + x = 15 + 3x
39 - 15 = 3x - x
24 = 2x
x = 12
So, it will take 12 weeks before Raymond owns as many CDs as Kendall. Thank you for pointing out the mistake.
Kendall owns 39 CDs and buys 1 more CD every week, so after x weeks, Kendall will own 39+x CDs.
Raymond owns 15 CDs and buys 3 CDs every week, so after x weeks, Raymond will own 15+3x CDs.
We want to find the number of weeks (x) when Raymond owns the same number of CDs as Kendall:
39 + x = 15 + 3x
39 - 15 = 3x - x
24 = 2x
x = 12
So, it will take 12 weeks before Raymond owns as many CDs as Kendall. Thank you for pointing out the mistake.
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