To find the area of the rectangle ABCD, we first need to find the length of the base and the height of the rectangle.
The base of the rectangle is the side AD, which has a length of 6 units (from 3 to -5 on the x-axis).
The height of the rectangle is the side AB, which has a length of 8 units (from 4 to 4 on the y-axis).
Therefore, the area of rectangle ABCD is base times height = 6 units * 8 units = 48 square units.
Since the x-axis and y-axis are labeled in units, the area of the rectangle is 48 square units or 48 square feet.
Therefore, the correct answer is 32 square feet.
Use the image to answer the question.
A coordinate plane shows the x-axis ranging from negative 9 to 9 in unit increments and the y-axis ranging from negative 11 to 11 in unit increments. Four plotted points upper A upper B upper C upper D are joined to form a rectangle. The coordinates of the plotted points are as follows: point upper A is left parenthesis 3 comma 4 right parenthesis, point upper B is left parenthesis negative 5 comma 4 right parenthesis, point upper C is left parenthesis negative 5 comma 8 right parenthesis, and point upper D is left parenthesis 3 comma 8 right parenthesis.
Find the area of rectangle ABCD in square feet.
(1 point)
Responses
32 feet
32 feet
24 feet
24 feet
32 square feet
32 square feet
−32 square feet
negative 32 square feet
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1 answer