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Question

A coordinate plane shows the x-axis ranging from negative 9 to 9 in unit increments and the y-axis ranging from negative 11 to 11 in unit increments. Six plotted points are joined to form a composite figure. The six plotted points are upper A, upper B, upper C, upper D, upper E, and upper F. The coordinates of the plotted points are as follows: point upper A is left parenthesis 2 comma negative 6 right parenthesis, point upper B is left parenthesis negative 5 comma negative 6 right parenthesis, point upper C is left parenthesis negative 5 comma 6 right parenthesis, point upper D is left parenthesis 6 comma 6 right parenthesis, point upper E is left parenthesis 6 comma 1 right parenthesis, and point upper F is left parenthesis 2 comma 1 right parenthesis.

Find the perimeter of the polygon in kilometers.

(1 point)
Responses

104 square kilometers
104 square kilometers

46 kilometers
46 kilometers

46 square kilometers
46 square kilometers

34 square kilometers
34 square kilometers
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Answer 1

To find the perimeter of the polygon, we need to add the lengths of all the sides.

Side AB: sqrt((2-(-5))^2 + (-6-(-6))^2) = sqrt(49 + 0) = 7
Side BC: sqrt((-5-(-5))^2 + (6-(-6))^2) = sqrt(0 + 144) = 12
Side CD: sqrt((6-(-5))^2 + (6-6)^2) = sqrt(121 + 0) = 11
Side DE: sqrt((6-6)^2 + (1-6)^2) = sqrt(0 + 25) = 5
Side EF: sqrt((6-2)^2 + (1-1)^2) = sqrt(16 + 0) = 4
Side FA: sqrt((2-(-5))^2 + (1-(-6))^2) = sqrt(49 + 49) = 7

Adding all these lengths together we get:
7 + 12 + 11 + 5 + 4 + 7 = 46

Therefore, the perimeter of the polygon is 46 kilometers.