Since line segment $\overline{QP}$ is tangent to the circle, we know that the radius of the circle is perpendicular to the tangent line at the point of tangency. Therefore, $\angle POQ$ is a right angle.
Since $\angle POQ$ is a right angle, we know that the sum of $\angle PQO$ and $\angle OQP$ is equal to 90 degrees.
Given that $\angle P = 28$ degrees, we can express $\angle PQO$ as 28 degrees and $\angle OQP$ as $90 - 28 = 62$ degrees.
Finally, we can calculate the value of $x$ as follows:
$x = \angle QOP = \angle PQO + \angle OQP = 28 + 62 = 90$ degrees
Therefore, the value of $x$ is 90 degrees.
Assume that lines that appear to be tangent are tangent. Point O is the center of the circle. Find the value of x if the m<P = 28
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