Asked by Natasha
a smokestack is 205 m high. from 2 points C and D on the same side of the smoke stacks base b, the angles of elevation to the top of the smokestack are 40 degrees and 36 degrees respectively. find the distance between C and D
Answers
Answered by
Reiny
I hope you made a diagram
I let the top of the smoke-stack be P and its bottom be Q
then in triangle PCD, angle C = 36º
angle CDP = 140º, thus angle CPD = 4º
triangle PDQ is right-angles, so
sin40 = 205/DP
DP = 40/sin40 = ....
then in the other triangle by the Sine Law
CD/sin4 = DP/sin36
CD = DPsin4/sin36
= ....
let me know what you got
I let the top of the smoke-stack be P and its bottom be Q
then in triangle PCD, angle C = 36º
angle CDP = 140º, thus angle CPD = 4º
triangle PDQ is right-angles, so
sin40 = 205/DP
DP = 40/sin40 = ....
then in the other triangle by the Sine Law
CD/sin4 = DP/sin36
CD = DPsin4/sin36
= ....
let me know what you got
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