x^2 + 18x + 32 = 0

Answer 1

To solve this quadratic equation, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = 18, and c = 32. Plugging these values into the formula, we get:

x = (-18 ± √(18^2 - 4*1*32)) / 2*1

x = (-18 ± √(324 - 128)) / 2

x = (-18 ± √196) / 2

x = (-18 ± 14) / 2

Now we can calculate the two possible solutions:

x1 = (-18 + 14) / 2 = -4 / 2 = -2

x2 = (-18 - 14) / 2 = -32 / 2 = -16

Therefore, the solutions to the equation x^2 + 18x + 32 = 0 are x = -2 and x = -16.