2.7 degrees Fahrenheit
Mean of Sample 1 = (78 + 82 + 85 + 87 + 90 + 85 + 79 + 86 + 91 + 88) / 10 = 85.1
Mean of Sample 2 = (81 + 79 + 80 + 86 + 89 + 92 + 82 + 88 + 84 + 87) / 10 = 84.8
Difference = Mean of Sample 1 - Mean of Sample 2 = 85.1 - 84.8 = 0.3
The mean daily high temperatures of the two samples differ by 0.3 degrees Fahrenheit.
Anthony wants to know the average daily high temperatures in his town during the summer. He chose two random samples of 10 consecutive days and recorded the daily high temperatures. The daily high temperatures in Fahrenheit are as follows.
Sample 1: 78 82 85 87 90
85
79 86 91 88
Sample 2: 81 79 80 86 89
92 82
88
84 87
Find the mean daily high temperatures of each sample and calculate the diference between these mean daily high temperatures.
2 points)
The mean daily high temperature of Sample 1 is
The mean daily high temperature of Sample 2 is
The mean daily high temperatures of the two samples differ by
1 answer