To find the perimeter of triangle JKL, we first need to find the lengths of JK, KL, and LJ.
Since JK and KL are tangent to circle O, we know that JA = AK and KC = CL. Therefore, JK = JA + AK = 15 + 18 = 33 and KL = KC + CL = 6 + 18 = 24.
Now, since JK¯¯¯¯¯¯¯¯, KL¯¯¯¯¯¯¯¯, and LJ¯¯¯¯¯¯¯ are all tangents to the circle O, we have LJ = LA + AJ = 18 + 15 = 33.
Therefore, the perimeter of triangle JKL is JK + KL + LJ = 33 + 24 + 33 = 90.
So the correct answer is 90.
JK¯¯¯¯¯¯¯¯, KL¯¯¯¯¯¯¯¯, LJ¯¯¯¯¯¯¯ are all tangent to circle O. The diagram is not drawn to scale. If JA = 15, AL = 18 and CK = 6, what is the perimeter of triangle JKL? (1 point) Responses
32 32
39 39
78 78
64
1 answer