To determine the limiting reactant, we must first calculate the moles of NO that would be produced by each reactant and then identify the reactant that produces the least amount of product.
From the balanced equation, we see that 1 mol of N2 reacts to form 2 mol of NO, and 1 mol of O2 reacts to form 2 mol of NO.
For N2:
2.25 mol N2 × 2 mol NO / 1 mol N2 = 4.50 mol NO.
For O2:
2.00 mol O2 × 2 mol NO / 1 mol O2 = 4.00 mol NO.
Since 4.00 mol of NO is less than 4.50 mol of NO, the limiting reactant is O2.
Therefore, with O2 as the limiting reactant, the maximum amount of moles of NO that form is 4.00 mol.
Use the balanced equation, N2 + O2 2NO, to answer the following questions.
Part: 0 / 3
Part 1 of 3
Determine the limiting reactant. Select the single best answer.
2.25 mol N2
2.00 mol O2
X
How many moles of the product NO form? Be sure your answer has the correct number of significant figures.
mol NO
1 answer