Question
A gallon of water weighs 8.34 pounds. The Patel family has a round,
12-foot diameter, above-ground pool. How much weight is added to the pool when it is filled with 3,110 gallons of water?
25,937.4 pounds
372.9 pounds
37,320 pounds
311,248.8 pounds
12-foot diameter, above-ground pool. How much weight is added to the pool when it is filled with 3,110 gallons of water?
25,937.4 pounds
372.9 pounds
37,320 pounds
311,248.8 pounds
Answers
GPT 3.5
The volume of the pool can be calculated using the formula for the volume of a cylinder: V = πr^2h
Given:
- Diameter of the pool = 12 feet, so the radius (r) = 6 feet
- Height of the pool (h) is not given, but not needed to calculate the weight of water
Volume of water in the pool = 3,110 gallons
Weight of water = 8.34 pounds/gallon
Weight of water added to the pool = 3,110 gallons x 8.34 pounds/gallon = 25,937.4 pounds
Therefore, the weight added to the pool when it is filled with 3,110 gallons of water is 25,937.4 pounds.
The correct option is: 25,937.4 pounds.
Given:
- Diameter of the pool = 12 feet, so the radius (r) = 6 feet
- Height of the pool (h) is not given, but not needed to calculate the weight of water
Volume of water in the pool = 3,110 gallons
Weight of water = 8.34 pounds/gallon
Weight of water added to the pool = 3,110 gallons x 8.34 pounds/gallon = 25,937.4 pounds
Therefore, the weight added to the pool when it is filled with 3,110 gallons of water is 25,937.4 pounds.
The correct option is: 25,937.4 pounds.