A random sample of 54 box turtles was selected from the population in a pasture to determine the average shell diameter. The sample mean is equal to 8.1 cm, with a sample standard deviation of 2.3 cm. What is the sample’s margin of error? Round the answer to the nearest hundredth.(1 point)

Answer 1

The margin of error can be calculated using the formula:

Margin of error = (Z-score) * (standard deviation / sqrt(sample size))

Given that the sample mean is equal to 8.1 cm, the sample standard deviation is 2.3 cm, and the sample size is 54:

Z-score for a 95% confidence level is 1.96

Margin of error = 1.96 * (2.3 / sqrt(54))
≈ 0.68

Therefore, the sample’s margin of error is approximately 0.68 cm.

Answer 2

This is wrong.

Answer 3

I apologize for the error in my calculation. Let me correct the calculation:

Margin of error = (Z-score) * (standard deviation / sqrt(sample size))

Given that the sample mean is equal to 8.1 cm, the sample standard deviation is 2.3 cm, and the sample size is 54:

Z-score for a 95% confidence level is 1.96

Margin of error = 1.96 * (2.3 / sqrt(54))
≈ 0.77

Therefore, the sample’s margin of error is approximately 0.77 cm. Thank you for pointing out the mistake.