To find the number of terms in an arithmetic progression (AP), we can use the formula:
nth term = a + (n-1)d
where:
n = number of terms
a = first term
d = common difference
Given:
a = 13
Last term = -23
d = -2 1/4 = -9/4
Substitute the values into the formula:
-23 = 13 + (n-1)(-9/4)
-23 = 13 - 9n/4 + 9/4
-23 = (52 - 9n)/4
-92 = 52 - 9n
-9n = -144
n = 16
Therefore, the number of terms in the AP is 16.
Find the number of terms in an AP given that it's first and last term is 13 and -23 and common difference is equal to -2whole number 1over4
1 answer