To solve this problem, we can use the combined gas law formula:
P1V1/T1 = P2V2/T2
Where:
P1 = initial pressure (740 mmHg)
V1 = initial volume (200 cm³)
T1 = initial temperature (27⁰C + 273 = 300 K)
P2 = final pressure (STP pressure = 760 mmHg)
V2 = final volume (to be calculated)
T2 = final temperature (STP temperature = 273 K)
Let's substitute the values into the formula:
(740 mmHg)(200 cm³)/(300 K) = (760 mmHg)(V2)/273 K
147000 mmHg*cm³/K = 760V2/273
V2 = (147000 mmHg*cm³/K)*(273 K)/(760 mmHg) ≈ 528.8 cm³
Therefore, the volume of the gas at STP is approximately 528.8 cm³.
A certain mass of a gas occupies 200cm³ at 27⁰c and the pressure of 740 mmttg determine the volume of the gas at S.T.P
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