Question
What is the surface area of the solid. 4cm, 2cm, 9cm
Answers
GPT 3.5
To calculate the surface area of a solid, we need to find the areas of all the surfaces and then sum them up.
Given that the solid has dimensions of 4cm, 2cm, and 9cm.
There are 6 surfaces in total for a rectangular solid:
- Top surface area = length x width = 4cm x 2cm = 8cm^2
- Bottom surface area = length x width = 4cm x 2cm = 8cm^2
- Front surface area = length x height = 4cm x 9cm = 36cm^2
- Back surface area = length x height = 4cm x 9cm = 36cm^2
- Left surface area = width x height = 2cm x 9cm = 18cm^2
- Right surface area = width x height = 2cm x 9cm = 18cm^2
Adding up the surface areas:
8cm^2 + 8cm^2 + 36cm^2 + 36cm^2 + 18cm^2 + 18cm^2 = 124cm^2
Therefore, the surface area of the solid is 124 square centimeters.
Given that the solid has dimensions of 4cm, 2cm, and 9cm.
There are 6 surfaces in total for a rectangular solid:
- Top surface area = length x width = 4cm x 2cm = 8cm^2
- Bottom surface area = length x width = 4cm x 2cm = 8cm^2
- Front surface area = length x height = 4cm x 9cm = 36cm^2
- Back surface area = length x height = 4cm x 9cm = 36cm^2
- Left surface area = width x height = 2cm x 9cm = 18cm^2
- Right surface area = width x height = 2cm x 9cm = 18cm^2
Adding up the surface areas:
8cm^2 + 8cm^2 + 36cm^2 + 36cm^2 + 18cm^2 + 18cm^2 = 124cm^2
Therefore, the surface area of the solid is 124 square centimeters.