The math club sold slices of pizza, P, a profit of three dollars each and cans of soda, S, at two dollars each to raise money for a trip. They sold 200 items and made a profit of $550 the pair Linear equations that model the situation

Answer 1

Let's denote the number of slices of pizza sold as x and the number of cans of soda sold as y.

Since each slice of pizza was sold at a profit of $3, the profit from selling x slices of pizza would be 3x.
Similarly, since each can of soda was sold at a profit of $2, the profit from selling y cans of soda would be 2y.

From the given information, we know that the total number of items sold was 200. So, we have:

x + y = 200

We also know that the total profit from selling both slices of pizza and cans of soda was $550. So, we have:

3x + 2y = 550

Therefore, the pair of linear equations that model the situation are:

1) x + y = 200
2) 3x + 2y = 550