Asked by Veronica
1) A wave with frequency 3.1 Hz and amplitude 2.7 cm moves in the positive x-direction with speed 5.6 m/s. Determine the wavelength.
2) The equation of a wave along the x-axis is given as: ξ cm = 3.4 sin (1.13 x - 0.75 t)
in which ξ is the displacement. Units on the right hand side are 1/cm for К and 1/s for ω.
Determine the the traveling speed of the wave.
2) The equation of a wave along the x-axis is given as: ξ cm = 3.4 sin (1.13 x - 0.75 t)
in which ξ is the displacement. Units on the right hand side are 1/cm for К and 1/s for ω.
Determine the the traveling speed of the wave.
Answers
Answered by
Damon
1) A wave with frequency 3.1 Hz and amplitude 2.7 cm moves in the positive x-direction with speed 5.6 m/s. Determine the wavelength.
Distance = rate * time
here the time is a period 1/f = 1/3.1
distance = 5.6 m/s * (1/3.1) s
Distance = rate * time
here the time is a period 1/f = 1/3.1
distance = 5.6 m/s * (1/3.1) s
Answered by
Damon
2) The equation of a wave along the x-axis is given as: ξ cm = 3.4 sin (1.13 x - 0.75 t)
in which ξ is the displacement. Units on the right hand side are 1/cm for К and 1/s for ω.
Determine the the traveling speed of the wave.
if x changes by L with no change in t, the argument of the sin increases by 2 pi
(1.13 x - 0.75 t) +2pi = 1.13 (x+L) -.75 t
so
2 pi = 1.13 L
L = 2 pi/1.13
if t changes by T with no change in x, the argument of the sine changes by 2pi
1.13x -.75 (t) = 1.13x -.75(t+T)+ 2 pi
2 pi = .75 T
T = 2 pi/.75
rate = distance/time = (2 pi/1.13) /(2 pi/.75) = .75/1.13
By the way, you can do this by looking for the constant phase speed
express the argument of the sine as
(2 pi/L)(x-vt)
then 2 pi/L x = 1.13 x
and (2 pi/L)(vt) = .75t
or
L = 2 pi/1.13
v = .75L/2 pi = .75/1.13 again
in which ξ is the displacement. Units on the right hand side are 1/cm for К and 1/s for ω.
Determine the the traveling speed of the wave.
if x changes by L with no change in t, the argument of the sin increases by 2 pi
(1.13 x - 0.75 t) +2pi = 1.13 (x+L) -.75 t
so
2 pi = 1.13 L
L = 2 pi/1.13
if t changes by T with no change in x, the argument of the sine changes by 2pi
1.13x -.75 (t) = 1.13x -.75(t+T)+ 2 pi
2 pi = .75 T
T = 2 pi/.75
rate = distance/time = (2 pi/1.13) /(2 pi/.75) = .75/1.13
By the way, you can do this by looking for the constant phase speed
express the argument of the sine as
(2 pi/L)(x-vt)
then 2 pi/L x = 1.13 x
and (2 pi/L)(vt) = .75t
or
L = 2 pi/1.13
v = .75L/2 pi = .75/1.13 again
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.