300 is divided into 2 parts so that half of one part may be less than other by 48.then the parts are?find the linear equation

Answer 1

Solution: Let x + y = 300, where x and y are two (parts)numbers
Given, x - y/2 = 48
=> x = 48 + y/2

Hence, 48 + y/2 + y = 300
3y/2 = 252
y = 2 X 252 / 3 = 504 / 3 = 168
x = 300 - 168 = 132
Hence, the two parts (numbers)are 132 and 168.

Answer 2

168 And 132

Answer 3

Let x+y=300,where x and yare two parts
Given,x-y/2 =48
=>x=48+y/2

Answer 4

Purr

Answer 5

Good

Answer 6

Brilliant 🙂🙂🙂