300 gm of water at 25°c is added to 100 gm of ice at 0°c.the temperature of the mixture is?

Answer 1

Since the subject is 'maths', I'm assuming the energy required for the ice-to-water conversion is not to be considered

Basically, you have to multiply the fraction of the total masses of the substance with their temperature:

Final Temp. = (300/400)*25 + (100/400)*0
= (3/4)*25
= 18.75 degrees Celsius

Answer 2

The answer is wrong zero is the answer